Answer
$\frac{1}{\sqrt[3] 2}$
Work Step by Step
$2^{\frac{1}{3}}2^{-1}2^{\frac{2}{3}}2^{-\frac{1}{3}}=2^{\frac{1}{3}-1}2^{\frac{2}{3}-\frac{1}{3}}=2^{-\frac{2}{3}}2^{\frac{1}{3}}=2^{-\frac{2}{3}+\frac{1}{3}}=2^{-\frac{1}{3}}=\frac{1}{2^{\frac{1}{3}}}=\frac{1}{\sqrt[3] 2}$
