Answer
$\lim\limits_{x \to 0} x^2 = 0$
Work Step by Step
Let $\epsilon \gt 0$ be given.
Let $\delta = \epsilon$
If $\vert x-0 \vert \lt \delta$, then $\vert x^2 - 0\vert \lt \delta = \epsilon$
Therefore, $\lim\limits_{x \to 0} x^2 = 0$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 2 - Section 2.4 - The Precise Definition of a Limit - 2.4 Exercises - Page 114: 25
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