Answer
Domain: $(-\infty, \frac{1}{3})\cup (\frac{1}{3}, \infty)$
Range: $(-\infty, 0)\cup (0, \infty)$
Work Step by Step
Domain: all real x except when $3x-1=0, x=\frac{1}{3}$
Range: When $x$ approaches $\pm\infty , y$ approaches $0$ as the denominator $3x-1$ becomes very large. So the range is all real $y$, except $y=0$.
