Answer
$300x^9+135x^8+105x^6+120x^3+45x^2+15$
Work Step by Step
$h(x)=(5x^7+5x)(6x^3+3x^2+3)$
Distribute: $h(x)=30x^{10}+15x^7+30x^4+15x^3+15x$
Now take the derivative using the power rule:
$h^{‘}(x)=300x^9+135x^8+105x^6+120x^3+45x^2+15$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 161: 71
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