Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 16 - Vector Calculus - 16.9 The Divergence Theorem - 16.9 Exercises - Page 1185: 8

Answer

$\dfrac{384 \pi}{5}$

Work Step by Step

Divergence Theorem: $\iiint_Ediv \overrightarrow{F}dV=\iint_S \overrightarrow{F}\cdot d\overrightarrow{S} $ where, $div F=\dfrac{\partial P}{\partial x}+\dfrac{\partial Q}{\partial y}+\dfrac{\partial R}{\partial z}=\dfrac{\partial (x^3+y^3)}{\partial x}+\dfrac{\partial (y^3+z^3)}{\partial y}+\dfrac{\partial (z^3+x^3)}{\partial z}=3x^2+3y^2+3z^2$ The spherical coordinates defines as: $dV=dxdydz=\rho^2 \sin \phi d \rho d\theta d\phi$ $\iiint_E (3x^2+3y^2+3z^2)dV=\int_{0}^{\pi}\int_0^{2 \pi} \int_0^{2} (3 \rho^2) \rho^2 \sin \phi d\rho d\theta d\phi$ $=\int_{0}^{\pi}\int_0^{2 \pi} \int_0^{2} (3 \rho^4) \sin \phi d\rho d\theta d\phi$ $=3 [-\cos \phi]_{0}^{\pi} [\theta]_0^{2 \pi} [\dfrac{\rho^5}{5}]_0^2$ $=(3)\times (2) \times (2 \pi) \times \dfrac{32}{5}$ Hence, we have $\iiint_Ediv \overrightarrow{F}dV=\iint_S \overrightarrow{F}\cdot d\overrightarrow{S}=\dfrac{384 \pi}{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.