Answer
$\frac{1}{\frac{1}{4}}e^{-\frac{x}{\frac{1}{4}}}$ = $4e^{-4x}$
Work Step by Step
$\frac{1}{\frac{1}{4}}e^{-\frac{x}{\frac{1}{4}}}$ = $4e^{-4x}$
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