Answer
$1960 \ J$
Work Step by Step
The work required to lift the segment of the chain to the top of the building can be computed as:
$W_{i} \approx (4 \Delta y) (9.8 y_i) \
J$
Therefore, the total work done when $\Delta y \to 0$ can be computed as:
$ W=\int_{2}^{10} 39.2 \ y \ dy \\=39.2 [\dfrac{y^2}{2}]_{2}^{10}\\=19.6 9 \times [y^2]_{2}^{10} \\= 1960 \ J$
