Answer
$16$
Work Step by Step
The average is given by
$$
\frac{1}{4-0} \int_{0}^{4} x^{3} d x=\frac{1}{4} \int_{0}^{4} x^{3} d x=\left.\frac{1}{16} x^{4}\right|_{0} ^{4}=16
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - 6.2 Setting Up Integrals: Volume, Density, Average Value - Exercises - Page 298: 39
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