Answer
$16 \pi \ \mathrm{g}.$
Work Step by Step
We know that the mass density is $\frac{4}{r}$. Thus, the total mass of the plate is
$$
2 \pi \int_{0}^{2} r\left(\frac{4}{r}\right) d r=2 \pi \int_{0}^{2} 4 d r=16 \pi \ \mathrm{g}.
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - 6.2 Setting Up Integrals: Volume, Density, Average Value - Exercises - Page 298: 34
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