Answer
$V$ = $\frac{16r^{3}}{3sinθ}$
Work Step by Step
$V$ = $\frac{4}{sinθ}\int_{-r}^{r}(r^{2}-y^{2})dy$
$V$ = $\frac{16r^{3}}{3sinθ}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - 6.2 Setting Up Integrals: Volume, Density, Average Value - Exercises - Page 297: 22
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