Chapter 6 - Applications of the Integral - 6.2 Setting Up Integrals: Volume, Density, Average Value - Exercises - Page 297: 16

$V$ = $\frac{\sqrt 3}{12}s^{2}h$

$\frac{h}{h-x}$ = $\frac{s}{x}$ $x$ = $\frac{s(s-x)}{h}$ $A$ = $\frac{\sqrt 3}{4}[\frac{s(h-x)}{h}]^{2}$ $V$ = $\int_0^{h}\frac{\sqrt 3}{4}[\frac{s(h-x)}{h}]^{2}dx$ $V$ = $\frac{\sqrt 3}{12}s^{2}h$