Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.6 Net Change as the Integral of a Rate of Change - Exercises - Page 268: 13

Answer

$39$ m/s

Work Step by Step

= $\int_1^4(8t-t^{2})dt$ = $4t^{2}-\frac{t^{3}}{3} |_1^4$ = $39$ m/s
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