Answer
displacement $0$ m
distance $1$ m
Work Step by Step
displacement
= $\int_{0.5}^{2}(t^{-2}-1)dt$
= $-t^{-1}-t |_{0.5}^{2}$
= $0$ m
distance
$t^{-2}-1$ = $0$
$t^{2}-1$ = $0$
$(t-1)(t+1)$ = $0$
$t$ = $-1,1$
= $\int_{0.5}^{1}(t^{-2}-1)dt$ + $\int_{1}^{2}(t^{-2}-1)dt$
= $-t^{-1}-t |_{0.5}^{1}$ + $-t^{-1}-t |_{1}^{2}$
= $1$ m
