Answer
$$12$$
Work Step by Step
We have
$$\int_{1/2}^{1} 8x^{-3}dx=\frac{1}{-2}8x^{-2}|_{1/2}^1=-4x^{-2}|_{1/2}^1=-4+16=12.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 258: 19
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