Answer
concave up $x$ > $4$
concave down $0$ < $x$ < $4$
inflection point is at $x$ = $4$
Work Step by Step
let
$f(x)$ = $x^{\frac{7}{2}}-35x^{2}$
$f'(x)$ = $\frac{7}{2}x^{\frac{5}{2}}-70x$
$f''(x)$ = $\frac{35}{4}x^{\frac{3}{2}}-70$
concave up
$\frac{35}{4}x^{\frac{3}{2}}-70$ > $0$
$x^{\frac{3}{2}}$ > $8$
$x$ > $4$
concave down
$0$ < $x$ < $4$
inflection point is at
$x$ = $4$