Answer
$$\frac{dy}{dx}=\frac{y+2x}{1-x}, \quad x\neq 1.$$
Work Step by Step
Simplify the given equation first by multiplying both sides by $ x $; We then have $ y=x^2+xy $. Now, by differentiating the equation $ y=x^2+xy $ with respect to $ x $, we get
$$\frac{dy}{dx}=2x+y+x \frac{dy}{dx}\Longrightarrow \frac{dy}{dx}(1-x)=y+2x $$
and hence
$$\frac{dy}{dx}=\frac{y+2x}{1-x}, \quad x\neq 1.$$
