Answer
$$ \frac{dy}{dx}=\frac{x^2}{y^2}.$$
Work Step by Step
By differentiating the equation $ x^3-y^3=4$ with respect to $ x $, we get
$$3x^2-3y^2\frac{dy}{dx}=0\Longrightarrow \frac{dy}{dx}=\frac{x^2}{y^2}.$$
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