Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.9 Related Rates - Exercises - Page 160: 17

Answer

0.675 m/s

Work Step by Step

Distance $x= velocity\times time= (1.2 \,m/s)t$ From the two similar triangles in the figure, we can write $\frac{5}{height\,of\,man}=\frac{x+y}{y}$ $\implies \frac{5}{1.8}=\frac{1.2\,t+y}{y}$ $\implies 2.777778=\frac{1.2\,t}{y}+1$ $\implies 1.777778= \frac{1.2\,t}{y}$ Or, $y= \frac{1.2\,t}{1.777778}=0.675\,t$ Hence, the rate at which the shadow is increasing is: $\frac{dy}{dt}=0.675\,m/s$
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