Answer
See the details below.
Work Step by Step
For $ y=\sin x $, we have
$$ y'=\cos x, \quad y''=-\sin x $$
and hence $ y''=-y $.
For $ y=\cos x $, we have
$$ y'=-\sin x, \quad y''=-\cos x $$
and hence $ y''=-y $.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.6 Trigonometric Functions - Exercises - Page 140: 38
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
