Answer
$$2xy^2$$
Work Step by Step
The mistake is to differentiate $ y^2$ with respect to $ x $ as $2y $. The correct formula is
$$\frac{\partial }{\partial x}(x^2y^2)=\frac{\partial x^2}{\partial x}y^2+\frac{\partial y^2}{\partial x}x^2=2xy^2+0=2xy^2.$$
