Answer
$$4x+ y-4z=0, \quad x+ y-4z=0$$
(Other answers are possible.)
Work Step by Step
The planes
$$4x+ y-4z=0, \quad x+ y-4z=0$$
have the trace $$ y-4z=0$$
in the $ yz $-plane. This is because, if we set $x=0$ in the equations, we will obtain the trace equation. Note that many other answers are possible.
