Answer
$$4x+3y+z=8, \quad 4x+3y+2z=8$$
(Other answers are possible.)
Work Step by Step
The planes
$$4x+3y+z=8, \quad 4x+3y+2z=8$$
have the trace $$4x+3y=8$$
in the $ xy $-plane. This is because, if we set $z=0$ in the equations, we will obtain the trace equation. Note that many other answers are possible.