Chapter 13 - Vector Geometry - 13.1 Vectors in the Plane - Exercises - Page 649: 3

See the figure below.

Assume that the terminal point of the vector $ a=\langle 1,3\rangle $, is $(x,y)$, then we have $$\langle 1,3\rangle =(x,y) - (2,2)\Longrightarrow x=3, \quad y=5$$ and hence $ a $ is based at $(2,2) $ and the terminal point at $(3,5)$. So, the equivalent vector to $ a $ and based at the origin is $\langle 1,3\rangle $ as in the following figure.