Chapter 13 - Vector Geometry - 13.1 Vectors in the Plane - Exercises - Page 649: 2

See the figure below.

Assume that the terminal point of the vector $ b=\langle 3,4\rangle $, is $(x,y)$, then we have $$\langle 3,4\rangle =(x,y) - (-2,-1)\Longrightarrow x=1, \quad y=3$$ and hence $ b $ is based at $(-2,-1) $ and the terminal point at $(1,3)$. So, we draw the vector $ b $ as in the following figure.