Answer
The conic section is a hyperbola.
directrix: $x=2$
eccentricity: $e=4$
Work Step by Step
Comparing the given equation with the standard form
$$
r=\frac{e d}{1+e \cos \theta}.
$$
We get $$ed=8, e=4.$$
We solve for $d$:
$d=\frac{8}{4}=2$
Thus, we see that the directrix is:
$x=2$
Since $e\gt 1$, then the conic section is a hyperbola.