Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.1 Parametric Equations - Exercises - Page 602: 1

At $t=0$, the coordinate is $(1,9)$. At $t=2$, the coordinate is $(9-3)$. At $t=4$, the coordinate is $(65,-39)$.

At $t=0$, then $x=1+t^3=1+0=1$ and $y=9-3t^2=9$. The coordinate is $(1,9)$. At $t=2$, then $x=1+t^3=1+8=9$ and $y=9-3t^2=9-12=-3$. The coordinate is $(9-3)$. At $t=4$, then $x=1+t^3=1+64=65$ and $y=9-3t^2=9-48=-39$. The coordinate is $(65,-39)$.