Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 11 - Infinite Series - Chapter Review Exercises - Page 591: 14

Answer

$b_m$ converges to $0$.

Work Step by Step

We have $$ \lim _{m \rightarrow \infty} b_m=\lim _{m \rightarrow \infty} \frac{1+(-1)^m}{m}\\ =\lim _{m \rightarrow \infty} \frac{(1/m)+((-1)^m/m)}{1}=0 $$ So, $b_m$ converges to $0$.
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