Answer
$$W \approx 10,330.3{\text{ ft - lb}}$$
Work Step by Step
$$\eqalign{
& {\text{Let the force }}F\left( x \right) = 100x\sqrt {125 - {x^3}} ,{\text{ on }}0 \leqslant x \leqslant 5 \cr
& {\text{The work done by the press is:}} \cr
& W = \int_a^b {F\left( x \right)} dx,{\text{ with }}F{\text{ in pounds and }}x{\text{ in feet}} \cr
& W = \int_0^5 {100x\sqrt {125 - {x^3}} } dx \cr
& {\text{Using a graphing utility}}\left( {{\text{scientific calculator}}} \right),{\text{we obtain:}} \cr
& W \approx 10,330.3{\text{ ft - lb}} \cr} $$
