Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 7 - Applications of Integration - 7.5 Exercises - Page 485: 39

Answer

$$W \approx 3249.443{\text{ft - lb}}$$

Work Step by Step

$$\eqalign{ & {\text{Let the force }}F\left( x \right) = 1000\left[ {1.8 - \ln \left( {x + 1} \right)} \right],{\text{ }}0 \leqslant x \leqslant 5 \cr & {\text{The work done by the press is:}} \cr & W = \int_a^b {F\left( x \right)} dx,{\text{ with }}F{\text{ in pounds and }}x{\text{ in feet}} \cr & W = \int_0^5 {1000\left[ {1.8 - \ln \left( {x + 1} \right)} \right]} dx \cr & {\text{Using a graphing utility}}\left( {{\text{scientific calculator}}} \right),{\text{we obtain:}} \cr & W \approx 3249.443{\text{ft - lb}} \cr} $$
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