Answer
about $ 64\%$
Work Step by Step
$P=\displaystyle \frac{2}{\pi}\int_{0}^{\pi/2}\sin\theta d\theta=[-\frac{2}{\pi}\cos\theta]_{0}^{\pi/2}$
$=-\displaystyle \frac{2}{\pi}(0-1)=\frac{2}{\pi}\approx$ 0.636619772368
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.4 Exercises - Page 291: 109
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