Answer
$f''(x)=\dfrac{2}{(x-6)^3}$
Work Step by Step
$f(x)=(x-6)^{-1}$
$f'(x)=(1)(-1)(x-6)^{-1-1}=-\dfrac{1}{(x-6)^2}=-(x-6)^{-2}.$
$f''(x)=(-1)(-2)(x-6)^{-2-1}=\dfrac{2}{(x-6)^3}.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.4 Exercises - Page 137: 87
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