Answer
$\lim\limits_{x \to -1} \frac{x^3-x^2}{x-1} = 1$
Work Step by Step
Using the rules of limits, we find:
$$\lim\limits_{x \to -1} \frac{x^3-x^2}{x-1} \\= \lim\limits_{x \to -1} \frac{x^2(x-1)}{x-1} \\= \lim\limits_{x \to -1} x^2 = (-1)^2 = 1 $$
