Answer
$\lim\limits_{\theta \to 0} tan(\frac{1-cos(\theta)}{\theta}) = 0$
Work Step by Step
By the squeeze theorem:
$\lim\limits_{x \to 0} \frac{1-cos(x)}{x} = 0$.
$\lim\limits_{\theta \to 0} tan(\frac{1-cos(\theta)}{\theta}) = \lim\limits_{\theta \to 0} tan(0) = 0$
