Answer
$\frac{dV}{dt} = 3x^2~\frac{dx}{dt}$
Work Step by Step
$V = x^3$
$\frac{dV}{dx} = 3x^2$
$\frac{dV}{dx}\cdot \frac{dx}{dt} = 3x^2~\frac{dx}{dt}$
$\frac{dV}{dt} = 3x^2~\frac{dx}{dt}$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 3 - Section 3.9 - Related Rates - 3.9 Exercises - Page 251: 1
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