Answer
$f(-3) = 5$
$f(0) = 5$
$f(2) = -2$
See graph
Work Step by Step
We have a piecewise function. For $f(-3)$ and $f(0)$, since $-3$ and $0$ belong to interval $(-\infty, 2)$ and the function $f$ is constant on the interval $(-\infty,2)$ we have:
$f(-3)=5$
$ f(0)=5$
Now we find the value of $f$ at $x=2$ which belongs to the interval $[2,\infty)$. So the function is defined
on this interval as
$f(x)=\frac{1}{2} x-3$………..(1)
Put $x=2$ into equation $(1)$, so we have
$f(2)=\frac{1}{2}(2)-3=1-3=-2$
The graph of a function is attached in the figure.
