Answer
Domain: $\{x|x\neq2\}$
Work Step by Step
The value of the function is underfined when the denominator is equal to $0$, which takes place when $x=2$. Therefore, domain is $\{x|x\neq2\}$.
However, we can also cancel it out as follows, $\frac{(x-2)(x+2)}{x-2}=x+2$, which means this is a removable discontinuity.
See the graph of the function.
