Answer
$\frac{19}{128} \ in, \frac{17}{128} \ in,\frac{1}{64}\ in$
Work Step by Step
The upper limit is the measurement + tolerance, that is,
$$
\frac{9}{64}+\frac{1}{128}=\frac{19}{128} \ in
.$$
The lower limit is the measurement - tolerance, that is,
$$
\frac{9}{64}-\frac{1}{128}=\frac{17}{128} \ in
.$$
The tolerance interval = upper limit-lower limit, that is,
$$
\frac{19}{128} \ in-\frac{17}{128} \ in=\frac{2}{128}\ in=\frac{1}{64}\ in
.$$
