Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Review - Page 208: 27

Answer

$5.88 \ m^2$

Work Step by Step

We divide as follows: $$ \frac{98.2 \ m^3}{16.7\ m}=5.88 \ m^2 .$$
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