Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Review - Page 208: 24

Answer

$4\bar{0}0 \ m$

Work Step by Step

Since $1 km =1000 m$ and $1m =100 cm$, we have $$ 16.8\ cm+19.7\ m+0.14 \ km+ 240 \ m\\ =0.168\ m+19.7\ m+140 \ m+ 240 \ m\\ =399.868 \ m \approx 4\bar{0}0 m .$$
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