Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 3 - Section 3.5 - Time, Current, and Other Units - Exercise - Page 149: 30

Answer

$$0.145 \ ns.$$

Work Step by Step

Since 1 ps =$10^{-12}$ s and 1 ns = $10^{-9} $ s, then 1 ps =$10^{-3}$ ns. So we have $$145 \ ps= 145\times 10^{-3} \ ns=0.145 \ ns.$$
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