Answer
$$350 \ mA.$$
Work Step by Step
Since $1 A=10^3$ mA, then we have
$$0.35 \ A=0.35 \times 10^3 \ mA=350 \ mA.$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 3 - Section 3.5 - Time, Current, and Other Units - Exercise - Page 149: 23
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