Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.4 - Signed Fractions - Exercises - Page 119: 46

Answer

$\frac{14}{15} $.

Work Step by Step

The given expression is $=\left (\frac{-4}{5} \right )\div\left (-1\frac{1}{2} \right )-\left (\frac{2}{-5} \right )$ Change to customary form. $=\left (-\frac{4}{5} \right )\div\left (-\frac{3}{2} \right )-\left (-\frac{2}{5} \right )$ Invert and multiply; cancel common terms. $=\left (-\frac{4}{5} \right )\times\left (-\frac{2}{3} \right )-\left (-\frac{2}{5} \right )$ The product is positive. $=\left (\frac{8}{15} \right )+\left (\frac{2}{5} \right )$ The LCD is $15$. $=\left (\frac{8}{15} \right )+\left (\frac{6}{15} \right )$ $=\frac{8+6}{15} $ $=\frac{14}{15} $.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.