Answer
52
Work Step by Step
Just as each digit of a standard Base 10 number has a place value that is a power of 10, each digit of a binary, or Base 2, number has a place value that is a power of 2. Reading right to left, the exponent starts at 0 and increases by 1.
$\underset\uparrow1\ \ \ \underset\uparrow1\ \ \ \underset\uparrow0\ \ \ \underset\uparrow1\ \ \ \underset\uparrow0\ \ \ \underset\uparrow0\ \ \ $
$2^5\ 2^4\ 2^3\ 2^2\ 2^1\ 2^0\longrightarrow$ place value
Multiply each non-zero digit by it's place value (using Base 10 computations) and find the sum of each.
$(1\times2^5) +(1\times2^4)+(1\times2^2)=32+16+4=52$
