Answer
13
Work Step by Step
Just as each digit of a standard Base 10 number has a place value that is a power of 10, each digit of a binary, or Base 2, number has a place value that is a power of 2. Reading right to left, the exponent starts at 0 and increases by 1.
$\underset\uparrow1\ \ \ \underset\uparrow1\ \ \ \underset\uparrow0\ \ \ \underset\uparrow1$
$2^3\ 2^2\ 2^1\ 2^0\longrightarrow$ place value
Multiply each non-zero digit by it's place value (using Base 10 computations) and find the sum of each.
$(1\times2^3) +(1\times2^2)+(1\times2^0)=8+4+1=13$
