Answer
The solution of the equation
$2\left( 5y-3 \right)+4\left( 6y-1 \right)=17\left( 2y-3 \right)-25y$
is
$y=-\frac{41}{25}$.
Work Step by Step
Solve the brackets first,
$\begin{align}
& 2\left( 5y-3 \right)+4\left( 6y-1 \right)=17\left( 2y-3 \right)-25y \\
& 10y-6+24y-4=34y-51-25y
\end{align}$
Solve further,
$\begin{align}
& 10y-6+24y-4=34y-51-25y \\
& 10y+24y-34y+25y-6-4+51=0 \\
& 25y+41=0 \\
& 25y=-41
\end{align}$
Simplify,
$y=-\frac{41}{25}$
