Answer
$A_{total}=1,5\bar{0}0~in^{2}$
$P=16\bar{0}~in$
Work Step by Step
To find the area:
We first calculate the area of the rectangle and the circle.
The area of the rectangle is $A=bh$, where $b=40.5in$ and $h=25in$.
So,
$A_{rectangle}=(40.5in)(25in)=1,012.5in^{2}$
The area of the circle can be calculated using the diameter with the formula $A=\frac{\pi}{4}d^{2}$, where $d=25in$.
So,
$A_{circle}=\frac{\pi}{4}(25in)^{2}=490.87in^{2}$
The total area is $A_{rectangle}+A_{circle}$.
$A_{total}=1,012.5in^{2}+490.87in^{2}=1,503.37in^{2}\approx 15\bar{0}0~in^2$
To find the perimeter:
The perimeter in this case is calculated with the formula $P=2b+\pi*d$ with the same values as above.
So,
$P=2(40.5in)+\pi(25in)=159.54in\approx160~in$
