Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.5 - Circles - Exercise - Page 411: 29

Answer

$A=1332~cm^{2}$

Work Step by Step

The area of the metal can be calculated by subtracting the areas of the two circles from the area of the rectangle: $A=bh-\frac{\pi}{4}d_{1}^{2}-\frac{\pi}{4}d_{2}^{2}$ Where $b=60cm$ $h=30cm$ $d_{1}=14cm$ $d_{2}=20cm$ So, we have: $A=(60cm)(30cm)-\frac{\pi}{4}(14cm)^{2}-\frac{\pi}{4}(20cm)^{2}=1331.9cm^{2}\approx1332~cm^2$
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