Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.2 - Quadrilaterals - Exercise - Page 392: 23

Answer

$$36 \ ft .$$

Work Step by Step

Since $1~ft= 12~in$, we have $$ Area=lw\Longrightarrow 180\ ft= l \times \frac{36}{12} \Longrightarrow l=\frac{108}{3}= 36 \ ft .$$
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