Answer
$16 \ in, \ 48\ in$
Work Step by Step
Since the area of a rectangle is $A=lw$, then we have
$$
A=lw\Longrightarrow 128=8l \Longrightarrow l=\frac{128}{8}=16 \ in
.$$
Moreover, the perimeter is
$$
2(16+8)=2(24)=48\ in
.$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 12 - Section 12.2 - Quadrilaterals - Exercise - Page 392: 19
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