Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.2 - Quadrilaterals - Exercise - Page 391: 14

Answer

$2\bar{0}~cm$

Work Step by Step

Since the area of a rectangle is length times width ($A=l w$), we have $$ l=\frac{A}{w}=\frac{280 \ cm^2}{ 14\ cm}=2\bar{0} \ cm .$$
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